15x^2-x-16=0

Solution for 15x^2-x-16=0 equation:

15x^2-x-16=0

We add all the numbers together, and all the variables

15x^2-1x-16=0

a = 15; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·15·(-16)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-31}{2*15}=\frac{-30}{30}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+31}{2*15}=\frac{32}{30}
=1+1/15
$